State and explain Raoult's law

Raoult's Law: It states that, "The partial vapour pressure of any volatile component of a solution is equal to vapour pressure of pure component multiplied by its fraction in the solution." Consider a solution of two components A, and A2. Mole fractions of A, and A are x and x2 respectively. Let P and P are the vapour pressures of A, and A, respectively.

Then according to Raoult's law, the partial pressure P and P₂ of two components are

P₁ = P°x

P₂ =P°x

Total vapour pressure is P. P=P+P₂

P = P °x + PX2

X₁ = 1-X2

putting this value in above equation P(1-x)+ Px= P - P° x2 + P₂ x2 P= (P-P) x2+ P